(2x)^2/(0.1-x)(0.2-x)=70

Solution for (2x)^2/(0.1-x)(0.2-x)=70 equation:

(2x)^2/(0.1-x)(0.2-x)=70

We move all terms to the left:

(2x)^2/(0.1-x)(0.2-x)-(70)=0


Domain of the equation: (0.1-x)(0.2-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.2-x!=-0.1

x∈R


We add all the numbers together, and all the variables

2x^2/(-1x+0.1)(-1x+0.2)-70=0

We multiply parentheses ..

2x^2/(+x^2-0.2x-0.1x+0.02)-70=0

We multiply all the terms by the denominator


2x^2-70*(+x^2-0.2x-0.1x+0.02)=0

We multiply parentheses

2x^2-70x^2-0x-0x-1.4=0

We add all the numbers together, and all the variables

-68x^2-2x-1.4=0

a = -68; b = -2; c = -1.4;
Δ = b2-4ac
Δ = -22-4·(-68)·(-1.4)
Δ = -376.8
Delta is less than zero, so there is no solution for the equation